20=10x-5x^2

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Solution for 20=10x-5x^2 equation: 



20=10x-5x^2

We move all terms to the left:

20-(10x-5x^2)=0

We get rid of parentheses

5x^2-10x+20=0

a = 5; b = -10; c = +20;
Δ = b2-4ac
Δ = -102-4·5·20
Δ = -300
Delta is less than zero, so there is no solution for the equation

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